Mathematical Methods (10/24.539)
II. Linear Differential Equations
Example 2.3 -- Solution via Operator Factorization
Problem Description:
Solve the following variable coefficient 2nd order equation by operator factorization:
![]()
Problem Solution:
1. First let’s write the original equation in operator form,
![]()
2. Now factor the operator L(D) as follows:
![]()
Checking this (just to be sure) shows that indeed this is the correct factorization (always be careful here), or

3. Now, let
. Therefore, we have
![]()
or
![]()
But this is a linear 1st order ODE with integrating factor
. Therefore,

and integration gives
![]()
4. Now we must solve
![]()
or
![]()
Again this is a linear 1st order ODE with integrating factor
![]()
Therefore,

Integrating both sides of this expression gives (see detailed integration by parts below):

or

Note:
Let’s do one example of integration by parts. Consider the following integral,![]()
Now let’s put this into the following form
![]()
where
![]()
![]()
Therefore, we have
![]()
or

|
|
|
|
|
10/24.539 Lecture Notes by Dr. J. R. White, UMass-Lowell (updated August 1998).
Return to Online Courses